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NEET 2022 Model Paper 1
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© examsnet.com
Question : 59
Total: 200
Amount of heat evolved when
500
c
m
3
of
0.2
M
H
2
S
O
4
is mixed with
200
c
m
3
of
0.5
M
N
a
O
H
solution is
11.4
k
J
2.85
k
J
5.71
k
J
28.5
k
J
Validate
Solution:
-
m
o
l
of
H
2
S
O
4
=
500
×
0.2
1000
=
0.1
m
o
l
-
m
o
l
of
H
+
=
2
×
0.1
=
0.2
m
o
l
-
m
o
l
of
N
a
O
H
=
200
×
0.5
1000
=
0.1
m
o
l
=
m
o
l
of
O
H
−
So, amount of heat evolved
=
57.1
×
0.1
=
5.71
k
J
© examsnet.com
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