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NEET 2022 Physics and Chemistry
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© examsnet.com
Question : 17
Total: 100
When two monochromatic lights of frequency,
v
and
v
2
are incident on a photoelectric metal, their stopping potential becomes
V
s
2
and
V
s
respectively. The threshold frequency for this metal is
[NEET-2022]
2
v
3
v
2
3
v
3
2
v
Validate
Solution:
👈: Video Solution
Since
k
max
=
e
V
s
=
h
v
−
φ
e
v
S
2
=
h
v
−
h
v
0
. . . (i)
e
v
S
=
h
v
2
−
h
v
0
. . . (ii)
1
2
[
h
v
2
−
h
v
0
]
=
h
v
−
h
v
0
⇒
h
v
0
−
h
v
0
2
=
h
v
−
h
v
4
⇒
h
v
0
2
=
3
h
v
4
v
0
=
3
v
2
* Language of question is wrongly framed. The values of stopping potentials should be interchanged.
© examsnet.com
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