Test Index

Class 12 NEET Chemistry Biomolecules Questions

Question : 64 of 79

Marks: +1, -0

\alpha\text{-D}

\beta\text{-D}

Solution:

Glucose forms a stable hemiacetal between the

-\mathrm{CHO}

group and the

-\mathrm{OH}

group on the

5^{\text{th}}

carbon. In this process the

1^{\text{st}}

C

' atom becomes asymmetric giving two isomers which differ in the configuration of the asymmetric carbon. These two isomers are called as anomers.

Go to Question:

Prev Question

Next Question