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Class 11 NEET Chemistry Chemical Thermodynamics
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© examsnet.com
Question : 64
Total: 94
The work done during the expansion of a gas from a volume of
4
d
m
3
to
6
d
m
3
against a constant external pressure of
3
a
t
m
is
(
1
L
a
t
m
=
101.32
J
)
(2004)
−
6
J
−
608
J
+
304
J
−
304
J
Validate
Solution:
Work
=
−
P
ext
×
volume change
=
−
3
×
101.32
×
(
6
−
4
)
=
6
×
101.32
=
−
607.92
J
≈
−
608
J
© examsnet.com
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