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Class 11 NEET Chemistry Equilibrium Questions Part 1

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Question : 1

Total: 100

The solubility of BaSO4 in water is 2.42×10−3gL−1 at 298 K. The value of its solubility product (Ksp) will be
(Given molar mass of BaSO4=233gmol−1)

1.08×10−10mol2L−2
1.08×10−12mol2L−2
1.08×10−8mol2L−2
1.08×10−14mol2L−2

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