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Class 11 NEET Chemistry Equilibrium Questions Part 1
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© examsnet.com
Question : 40
Total: 100
If pH of a saturated solution of
B
a
(
O
H
)
2
is 12,the value of its
K
s
p
is
(2010,2012)
4.00
×
10
−
6
4.00
×
10
−
7
5.00
×
10
−
6
5.00
×
10
−
7
Validate
Solution:
p
H
of solution
=
12
[
H
+
]
=
10
−
12
[
O
H
−
]
=
10
−
14
10
−
12
=
10
−
2
B
a
(
O
H
)
2
⇌
B
a
2
+
+
2
O
H
−
s 2s
2
s
=
10
−
2
⇒
s
=
10
−
2
2
s
K
s
p
=
(
s
)
(
2
s
)
2
=
4
s
3
=
4
×
(
10
−
2
2
)
3
=
4
8
×
10
−
6
=
5
×
10
−
7
© examsnet.com
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