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Test Index
Class 11 NEET Chemistry Equilibrium Questions Part 2
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© examsnet.com
Question : 7
Total: 24
Consider the following reaction in a sealed vessel at equilibrium with concentrations of
N
2
=
3.0
×
10
−
3
M
,
O
2
=
4.2
×
10
−
3
M
and
NO
=
2.8
×
10
−
3
M
.
2
NO
(
g
)
⇌
N
2
(
g
)
+
O
2
(
g
)
If
0.1
mol
L
L
−
1
of
NO
(
g
)
is taken in a closed vessel, what will be degree of dissociation (
α
) of
NO
(
g
)
at equilibrium?
[NEET 2024]
0.00889
0.0889
0.8889
0.717
Validate
Solution:
👈: Video Solution
2
NO
(
g
)
⇌
N
2
(
g
)
+
O
2
(
g
)
K
c
=
[
N
2
]
[
O
2
]
[
NO
]
2
=
3
×
10
−
3
×
4.2
×
10
−
3
2.8
×
10
−
3
×
2.8
×
10
−
3
=
1.607
2
NO
(
g
)
⇌
N
2
(
g
)
+
O
2
(
g
)
t
=
0
0.1
0
0
0.1
–
0.1
α
0.05
α
0.05
α
K
c
=
0.05
α
×
0.05
α
(
0.1
−
0.1
α
)
2
K
c
=
0.05
α
×
0.05
α
0.01
(
1
−
α
)
2
1.607
=
(
0.05
)
2
α
2
0.01
(
1
−
α
)
2
α
2
(
1
−
α
)
2
=
1.607
×
(
0.1
)
2
(
0.05
)
2
α
1
−
α
=
1.27
×
0.1
0.05
α
1
−
α
=
2.54
α
=
2.54
−
2.54
α
3.54
α
=
2.54
α
=
2.54
3.54
=
0.717
© examsnet.com
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