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Class 11 NEET Chemistry Hydrocarbons Questions

Section: Chemistry

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Question : 9 of 102

Marks: +1, -0

The alkane that can be oxidized to the corresponding alcohol by

\mathrm{KMnO}_4

as per the equation

R_2-\overset{\vert}{\mathrm{C}}\underset{R_3}{\underset{\vert}{R_1}}-H\xrightarrow[]{\mathrm{KMnO}_4}R_2-\overset{\vert}{\mathrm{C}}\overset{R_1}{\underset{R_3}{\vert}}-OH

$R_1=H;R_2=H;R_3=H$
$R_1=\mathrm{CH}_3;R_2=\mathrm{CH}_3;R_3=\mathrm{CH}_3$
$R_1=\mathrm{CH}_3;R_2=H;R_3=H$
$R_1=\mathrm{CH}_3;R_2=\mathrm{CH}_3;R_3=H$

Solution:

Generally alkanes resist oxidation but alkane with tertiary H atom(s) can be oxidised to corresponding alcohols by

\mathrm{KMnO}_4

R_2-\overset{\vert}{\mathrm{C}}\overset{\mathrm{CH}_3}{\underset{\mathrm{CH}_3}{\vert}}-H\xrightarrow[\text{Oxidation}]{\mathrm{KMnO}_4}H_3C-\overset{\vert}{\mathrm{C}}\overset{\mathrm{CH}_3}{\underset{\mathrm{CH}_3}{\vert}}-OH

\therefore R_1\Rightarrow\mathrm{CH}_3\;\;R_2\Rightarrow\mathrm{CH}_3\;\;R_3\Rightarrow\mathrm{CH}_3

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