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Class 12 NEET Chemistry P Block Elements Questions
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© examsnet.com
Question : 40
Total: 101
Oxidation states of P in
H
4
P
2
O
5
,
H
4
P
2
O
6
,
H
4
P
2
O
7
are respectively
(2010)
+
3
,
+
5
,
+
4
+
5
,
+
3
,
+
4
+
5
,
+
4
,
+
3
+
3
,
+
4
,
+
5
Validate
Solution:
The oxidation state can be calculated as :
H
4
P
2
O
5
+
4
+
2
x
+
5
(
−
2
)
=
0
2
x
−
6
=
0
x
=
+
3
H
4
P
2
O
6
+
4
+
2
x
+
6
(
−
2
)
=
0
2
x
−
8
=
0
x
=
+
4
H
4
P
2
O
7
+
4
+
2
x
+
7
(
−
2
)
=
0
2
x
−
10
=
0
2
x
=
10
x
=
+
5
© examsnet.com
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