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Class 11 NEET Chemistry Redox Reactions Questions
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© examsnet.com
Question : 19
Total: 27
Oxidation numbers of P in
P
O
4
3
−
, of S in
S
O
4
2
−
and that of Cr in
C
r
2
O
7
2
−
are respectively
(2009)
+3,+6 and +5
+5,+3 and +6
+3,+6 and +6
+5,+6 and +6
Validate
Solution:
Let oxidation number of P in
P
O
4
3
−
be x
∴
x
+
4
(
−
2
)
=
−
3
⇒
x
=
+
5
Let oxidation number of S in
S
O
4
2
−
be y
∴
y
+
4
(
−
2
)
=
−
2
⇒
y
=
+
6
Let oxidation numbers of Cr in
C
r
2
O
7
2
−
be z.
∴
2
z
+
7
(
−
2
)
=
−
2
⇒
z
=
+
6
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