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Class 11 NEET Chemistry Structure Of Atom Questions
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© examsnet.com
Question : 49
Total: 82
The energy of second Bohr orbit of the hydrogen atom is
−
328
k
J
m
o
l
−
1
; hence the energy of fourth Bohr orbit would be
(2005)
−
41
k
J
m
o
l
−
1
−
82
k
J
m
o
l
−
1
−
164
k
J
m
o
l
−
1
−
1312
k
J
m
o
l
−
1
Validate
Solution:
E
n
=
−
K
(
Z
n
)
2
Z
=
1
for hydrogen;
n
=
2
E
2
=
−
K
×
1
4
⇒
E
2
=
−
328
k
J
m
o
l
−
1
;
K
=
4
×
328
E
4
=
−
K
×
1
16
⇒
E
4
=
−
4
×
328
×
1
16
=
−
82
k
J
m
o
l
−
1
© examsnet.com
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