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NEET Exam Model Paper 10
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© examsnet.com
Question : 17
Total: 180
Which one of the following statements is true for the speed v and the acceleration a of a particle executing simple harmonic motion ?
When v is maximum, a is minimum
Value of a is zero, whatever may be the value of v
When v is zero, a is zero
When v is maximum, a is zero
Validate
Solution:
In simple harmonic motion, the displacement equation is,
y
=
A
s
i
n
t
Where A is amplitude of the motion.
Velocity,
v
=
d
y
d
t
=
A
ω
c
o
s
ω
t
v
=
A
ω
=
√
1
−
s
i
n
2
ω
t
V
=
ω
√
A
2
−
y
2
.........(i)
Acceleration,
a
=
d
v
d
t
=
d
d
t
(
A
ω
c
o
s
ω
t
)
a
=
−
A
ω
2
s
i
n
ω
t
a
=
−
ω
2
y
...........(ii)
When,
y
=
0
;
v
=
A
ω
=
v
max
a
=
0
=
a
min
When
y
=
A
;
v
=
0
=
v
min
a
=
−
ω
2
A
=
a
,
max
Hence, it is clear that when v is maximum,then a is minimum (i.e., zero) or vice versa
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