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NEET Exam Model Paper 8
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© examsnet.com
Question : 22
Total: 180
A smooth block is released at rest from an inclined plane of inclination
45
°
and is allowed to slide a distance.
′
d
′
Now same block is released on a similar rough inclined plane and allowed to slide the same distance. The time taken by block to slide on rough plane is
′
n
′
times the time taken by it on a smooth plane. Then whatwould be the coefficient of friction for the rough inclined plane?
µ
k
=
√
1
−
1
n
2
µ
k
=
1
−
1
n
2
µ
s
=
√
1
−
1
n
2
µ
s
=
1
−
1
n
2
Validate
Solution:
d
=
1
2
(
g
s
i
n
θ
)
t
1
2
,
d
=
1
2
(
g
s
i
n
θ
−
µ
g
c
o
s
θ
)
t
2
2
t
1
=
√
2
d
g
s
i
n
θ
,
t
2
=
√
2
d
g
s
i
n
θ
−
µ
g
c
o
s
θ
According to question,
t
2
=
n
t
1
n
√
2
d
g
s
i
n
θ
=
√
2
d
g
s
i
n
θ
−
µ
g
c
o
s
θ
µ
,as applicable here, is coefficient of kinetic friction as the block moves over the inclined plane
n
=
1
√
1
−
µ
k
(
∵
c
o
s
45
°
=
45
°
,
1
√
2
)
n
2
=
1
1
−
µ
k
or
1
−
µ
k
=
1
n
2
or
µ
k
=
1
−
1
n
2
© examsnet.com
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