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NEET Odisha 2019 Physics and Chemistry
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© examsnet.com
Question : 4
Total: 90
A tuning fork with frequency
800
Hz
produces resonance in a resonance column tube with upper end open and lower end closed by water surface. Successive resonance are observed at length
9.75
cm
,
31.25
cm
and
52.75
cm
. The speed of sound in air is :-
[NEET OD 2019]
500
m
∕
s
156
m
∕
s
344
m
∕
s
172
m
∕
s
Validate
Solution:
👈: Video Solution
Here
λ
=
2
(
l
2
−
l
1
)
where
l
1
=
9.75
cm
,
l
2
=
31.25
cm
so
v
=
2
n
(
l
2
−
l
1
)
=
2
×
800
(
31.25
−
9.75
)
=
344
m
∕
s
© examsnet.com
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