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Class 12 NEET Physics Current Electricity Questions Part 1
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© examsnet.com
Question : 34
Total: 100
A current3 amp. flows through the
2
Ω
resistor
r
shown in the circuit. The power dissipated in the 5 Ω resistor is
(2008)
1 watt
5 watt
4 watt
2 watt
Validate
Solution:
2
Ω
,
4
Ω
and
(
1
Ω
+
5
Ω
)
are in parallel. So potential difference is the same.
V
=
2
Ω
.
i
1
=
4
Ω
.
i
2
=
6
Ω
.
i
3
2
.
3
=
6
Ω
.
i
3
⇒
i
3
=
1
a
m
p
.
Total P.D.
=
5
×
1
+
1
×
1
=
6
V
.
∴
Power dissipated in
5
Ω
resistance
=
V
′
2
R
where
V
′
is the P.D. across
5
Ω
=
5
V
.
∴
Power
=
25
5
Ω
=
5
watt
© examsnet.com
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