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Test Index
Class 12 NEET Physics Dual Nature of Matter and Radiation
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© examsnet.com
Question : 12
Total: 104
The number of photons per second on an average emitted by the source of monochromatic light of wavelength
600
n
m
, when it delivers the power of
3.3
×
10
−
3
watt will be
(
h
=
6.6
×
10
−
34
J
s
)
[NEET 2021]
10
18
10
17
10
16
10
15
Validate
Solution:
👈: Video Solution
The power of a source is given as
P
=
E
t
=
n
t
(
h
c
λ
)
⇒
n
t
=
P
(
h
c
λ
)
(Here
n
t
is number of photons emitted per second)
⇒
n
t
=
3.3
×
10
−
3
×
6
×
10
−
7
6.6
×
10
−
34
×
3
×
10
8
=
10
16
photons per second
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