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Class 12 NEET Physics Dual Nature of Matter and Radiation
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© examsnet.com
Question : 34
Total: 104
An α-particle moves in a circular path of radius 0.83 cm in the presence of a magnetic field of
0.25
W
b
/
m
2
. The de-Broglie wavelength associated with the particle will be
(2012)
1 Å
0.1 Å
10 Å
0.01 Å
Validate
Solution:
Radius of the circular path of a charged particle in a magnetic field is given by
R
=
m
v
B
q
or
m
v
=
R
B
q
Here,
R
=
0.83
c
m
=
0.83
×
10
−
2
B
=
0.25
W
b
m
−
2
q
=
2
e
=
2
×
1.6
×
10
−
19
C
∴
m
v
=
(
0.83
×
10
−
2
)
(
0.25
)
(
2
×
1.6
×
10
−
19
)
de Broglie wavelength,
λ
=
h
m
v
=
6.6
×
10
−
34
0.83
×
10
−
2
×
0.25
×
2
×
1.6
×
10
−
19
=
0.01
Å
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