Let the capacitances are C1 and C2 In series C‌eff ‌=3µF ⇒‌
C1C2
C1+C2
=3µF‌‌....‌ (i) ‌ In parallel C‌eff ‌=16µF ⇒C1+C2=16µF‌‌‌⋅⋅⋅⋅⋅⋅⋅(ii) From (i) & (ii) C1C2=48µF (C1−C2)2=(C1+C2)2−4C1C2 C1−C2=8µF‌‌......‌ (iii) ‌ From (ii) & (iii) C1=12µF,C2=4µF