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Class 12 NEET Physics Electrostatics Questions Part 1
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Question : 49
Total: 100
Two positive ions, each carrying a charge q, are separated by a distance d. If F is the force of repulsion between the ions, the number of electrons missing from each ion will be (e being the charge on an electron)
(2010)
4
π
ε
0
F
d
2
e
2
√
4
π
ε
0
F
e
2
d
2
√
4
π
ε
0
F
d
2
e
2
4
π
ε
0
F
d
2
q
2
Validate
Solution:
According to Coulomb’s law, the force of repulsion between the two positive ions each of charge q, separated by a distance d is given by
F
=
1
4
π
ε
0
(
q
)
(
q
)
d
2
;
F
=
q
2
4
π
ε
0
d
2
;
q
2
=
4
π
ε
0
F
d
2
q
=
√
4
π
ε
0
F
d
2
...........(i)
Since,
q
=
n
e
Where, n = number of electrons missing from each ion
e = magnitude of charge on electron
∴
n
=
q
e
=
√
4
π
ε
0
F
d
2
e
2
(Using (i))
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