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Class 12 NEET Physics Electrostatics Questions Part 1
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Question : 65
Total: 100
A parallel plate air capacitor is charged to a potential difference of
V
volts. After disconnecting the charging battery the distance between the plates of the capacitor is increased using an insulating handle. As a result the potential difference between the plates
(2006)
increases
decreases
does not change
becomes zero
Validate
Solution:
Capacitance of a parallel plate capacitor
C
=
ε
0
A
d
Also Capacitance
=
Charge
Potential difference
When battery is disconnected and the distance between the plates of the capacitor is increased then capacitance decreases and charge remains constant.
since Charge = Capacitance × Potential difference
∴ Potential difference increases.
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