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Class 11 NEET Physics Gravitation Questions
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© examsnet.com
Question : 19
Total: 83
The time period of a geostationary satellite is
24
h
, at a height
6
R
E
(
R
E
.
is radius of earth) from surface of earth. The time period of another satellite whose height is
2.5
R
E
from surface will be,
[NEET OD 2019]
6
√
2
h
12
√
2
h
24
2.5
h
12
2.5
h
Validate
Solution:
👈: Video Solution
Kepler's Third Law :-
T
∝
r
3
∕
2
T
2
T
1
=
(
r
2
r
1
)
3
∕
2
=
(
R
+
2.5
R
R
+
6
R
)
3
∕
2
=
1
2
√
2
⇒
T
2
=
24
2
√
2
=
6
√
2
hours
© examsnet.com
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