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Class 11 NEET Physics Gravitation Questions
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© examsnet.com
Question : 34
Total: 83
A body of mass ‘m’ is taken from/the earth’s surface to the height equal to twice the radius (R) of the earth. The change in potential energy of body will be
(2013 NEET)
3
m
g
R
1
3
m
g
R
m
g
2
R
2
3
m
g
R
Validate
Solution:
Gravitational potential energy at any point at a distance r from the centre of the earth is
U
=
−
G
M
m
r
where M and m be masses of the earth and the body respectively. At the surface of the earth, r = R
∴
U
i
=
−
G
M
m
R
At height h from the surface,
r
=
R
+
h
=
R
+
2
R
∵h=2R(Given)
=
3
R
∴
U
f
=
−
G
M
m
3
R
Change in potential energy,
Δ
U
=
U
f
−
U
i
=
−
G
M
m
3
R
−
(
−
G
M
m
R
)
=
G
M
m
R
(
1
−
1
3
)
=
2
3
G
M
m
R
=
2
3
m
g
R
(
∵
g
=
G
M
R
2
)
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