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Class 11 NEET Physics Gravitation Questions
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© examsnet.com
Question : 40
Total: 83
A geostationary satellite is orbiting the earth at a height of 5R above that surface of the earth, R being the radius of the earth. The time period of another satellite in hours at a height of 2R from the surface of the earth is
(2012)
5
10
6
√
2
6
√
2
Validate
Solution:
According to Kepler’s third law
T
2
∝
r
3
2
∴
T
2
T
1
=
(
r
2
r
1
)
3
2
=
(
R
+
2
R
R
+
5
R
)
3
2
=
1
2
3
2
T
2
24
=
1
2
3
2
or
T
2
=
24
2
3
2
=
24
2
√
2
=
6
√
2
hours
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