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Class 11 NEET Physics Laws of Motion Questions
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© examsnet.com
Question : 45
Total: 75
The coefficient of static friction,
µ
s
between block
A
of mass
2
kg
and the table as shown in the figure is 0.2.
What would be the maximum mass value of block
B
so that the two blocks do not move? The string and the pulley are assumed to be smooth and massless.
(
g
=
10
m
∕
s
2
)
( 2004 )
2.0
kg
4.0
kg
0.2
kg
0.4
kg
Validate
Solution:
Free body diagram of two masses is
We get equations
T
+
m
a
=
f
µ
or
T
=
µ
N
A
(
for
a
=
0
)
and
T
=
m
a
+
m
g
or
T
=
m
B
g
(for a = 0)
∴
µ
N
A
=
m
B
g
⇒
m
B
=
µ
m
A
=
0.2
×
2
=
0.4
kg
© examsnet.com
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