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Class 11 NEET Physics Laws of Motion Questions
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© examsnet.com
Question : 56
Total: 75
If the force on a rocket, moving with a velocity of
300
m
∕
s
is
210
N
,
then the rate of combustion of the fuel is
( 1999 )
0.07
kg
∕
s
1.4
kg
∕
s
0.7
kg
∕
s
10.7
kg
∕
s
Validate
Solution:
Force
=
d
d
t
(momentum)
=
d
d
t
(
m
v
)
=
v
(
d
m
d
t
)
⇒
210
=
300
(
d
m
d
t
)
d
m
d
t
=
rate of combustion
=
210
300
=
0.7
kg
∕
s
© examsnet.com
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