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Class 12 NEET Physics Moving Charges and Magnetism
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© examsnet.com
Question : 62
Total: 96
A galvanometer of 50 ohm resistance has 25 divisions. A current of
4
×
10
−
4
ampere gives a deflection of one division. To convert this galvanometer into a voltmeter having a range of 25 volts, it should be connected with a resistance of
(2004)
2500
Ω
as a shunt
2450
Ω
as a shunt
2550
Ω
in series
2450
Ω
in series.
Validate
Solution:
The total current shown by the galvanometer
=
25
×
4
×
10
−
4
A
∴
I
g
=
10
−
2
A
The value of resistance connected in series toconvert galvanometer into voltmeter of
25
V
is
R
=
V
I
g
−
G
=
25
10
−
2
−
50
=
2450
Ω
© examsnet.com
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