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Class 12 NEET Physics Moving Charges and Magnetism
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© examsnet.com
Question : 79
Total: 96
Two parallel wires in free space are
10
c
m
apart and each carries a current of
10
A
in the same direction. The force exerted by one wire on the other, per metre length is
(1997)
2
×
10
−
4
N
,
repulsive
2
×
10
−
7
N
,
repulsive
2
×
10
−
4
N
, attractive
2
×
10
−
7
N
, attractive.
Validate
Solution:
Distance between two parallel wires
(
x
)
=
10
c
m
=
0.1
m
;
Current in each wire
=
I
1
=
I
2
=
10
A
and length of wire
(
l
)
=
1
m
.
Force on the wire
(
F
)
=
µ
0
I
1
.
I
2
×
l
2
π
x
=
(
4
π
×
10
−
7
)
×
10
×
10
×
1
2
π
×
0.1
=
2
×
10
−
4
N
since the current is flowing in the same direction, therefore the force will be attractive.
© examsnet.com
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