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Class 12 NEET Physics Optics Questions Part 2

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Question : 28 of 59

Marks: +1, -0

Two transparent media

A

B

are separated by a plane boundary. The speed of light in those media are

1.5 \times 10^{8} \text{ m/s}

2.0 \times 10^{8} \text{ m/s}

, respectively. The critical angle for a ray of light for these two media is

$\sin^{-1}(0.500)$
$\tan^{-1}(0.500)$
$\sin^{-1}(0.750)$
$\tan^{-1}(0.750)$

Solution: 👈: Video Solution

\mu_{A}=\frac{3 \times 10^{8}}{1.5 \times 10^{8}}=2

\mu_{B}=\frac{3 \times 10^{8}}{2 \times 10^{8}}=1.5

For TIR, ray of light should travel from denser to rarer medium

\mu_{A} \sin \theta_{C}=\mu_{B} \sin 90^{\circ}

2 \sin \theta_{C}=1.5 \sin 90^{\circ}

\sin \theta_{C}=0.75

\theta_{C}=\sin^{-1}(0.75)

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