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Class 11 NEET Physics Oscillations Questions
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© examsnet.com
Question : 12
Total: 71
The displacement of a particle executing simple harmonic motion is given by
y
=
A
0
+
A
sin
ω
t
+
B
cos
ω
t
Then the amplitude of its oscillation is given by :
[NEET 2019]
√
A
2
+
B
2
√
A
0
2
+
(
A
+
B
)
2
A + B
A
0
+
√
A
2
+
B
2
Validate
Solution:
👈: Video Solution
y
=
A
0
+
A
sin
ω
t
+
B
cos
ω
t
Equate SHM
y
′
=
y
−
A
0
=
A
sin
ω
t
+
B
cos
ω
t
Resultant amplitude
R
=
√
A
2
+
B
2
+
2
A
B
cos
90
°
=
√
A
2
+
B
2
© examsnet.com
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