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Class 11 NEET Physics Oscillations Questions
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© examsnet.com
Question : 7
Total: 71
Two pendulums of length
121
c
m
and
100
c
m
start vibrating in phase. At some instant, the two are at their mean position in the same phase. The minimum number of vibrations of the shorter pendulum after which the two are again in phase at the mean position is:
[NEET-2022]
11
9
10
8
Validate
Solution:
👈: Video Solution
T
=
2
π
√
L
g
Let
n
1
and
n
2
be integer.
n
1
T
1
=
n
2
T
2
2
π
n
1
√
1.21
g
=
2
π
n
2
√
1.00
g
⇒
n
2
n
1
=
11
10
∴
After completion of
11
th
oscillation of shorter pendulum, it will be in phase with longer pendulum.
© examsnet.com
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