NEET Biology Complete Course by Moniba Madam - Watch Full Playlist

Test Index

Class 11 NEET Physics Physical World, Units and Measurements

© examsnet.com

Question : 8 of 75

Marks: +1, -0

Consider the diameter of a spherical object being measured with the help of a Vernier callipers. Suppose its 10 Vernier Scale Divisions (V.S.D.) are equal to its 9 Main Scale Divisions (M.S.D.). The least division in the M.S. is 0.1 cm and the zero of V.S. is at

x=0.1 \text{cm}

when the jaws of Vernier callipers are closed.

If the main scale reading for the diameter is

M=5 \text{cm}

and the number of coinciding vernier division is 8 , the measured diameter after zero error correction, is

4.98 cm
5.00 cm
5.18 cm
5.08 cm

Solution: 👈: Video Solution

\quad\text{Least count}=1 \text{MSD}-1 \text{VSD}

\;=1 \text{MSD}-\frac{9}{10} \text{MSD}

\;=\frac{1}{10} \text{MSD}

\;=\frac{1}{10} \times 0.1 \text{cm}=0.01 \text{cm}

\quad\text{Zero error}=+0.1 \text{cm}

\quad\text{Main scale reading}=5 \text{cm}

\quad\text{Vernier scale reading}=8 \times 0.01=0.08 \text{cm}

\quad\text{Final measurement of diameter}

\;=5+0.08-0.1=4.98 \text{cm}

© examsnet.com

Go to Question:

Prev Question

Next Question