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Class 12 NEET Physics Semiconductor Electronics Part 1
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© examsnet.com
Question : 11
Total: 100
The input resistance of a silicon transistor is
100
Ω
current is changed by
40
µ
A
which results in a change in collector currently by 2 mA. This transistor is used as a common emitter amplifier with a load resistance of
4
k
Ω
.The voltage gain of the amplifier is
(2012 Mains)
2000
3000
4000
1000
Validate
Solution:
Here,
Input resistance,
R
i
=
100
Ω
Change in base current,
Δ
I
B
=
40
µ
A
Change in collector current,
Δ
I
C
=
2
m
A
Load resistance,
R
L
=
4
k
Ω
=
4
×
10
3
Ω
Current gain,
β
=
Δ
I
C
Δ
I
B
=
2
m
A
40
µ
A
=
2
×
10
−
3
A
40
×
10
−
6
A
=
50
Voltage gain of the amplifier is
A
V
=
β
=
R
L
R
i
=
50
×
4
×
10
3
100
=
2000
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