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Class 12 NEET Physics Semiconductor Electronics Part 1
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© examsnet.com
Question : 76
Total: 100
The diode used in the circuit shown in the figure has a constant voltage drop at
0.5
V
at all currents and a maximum power rating of 100 milli watts. What should be the value of the resistor
R
, connected in series with diode for obtaining maximum current?
(1997)
6.76
Ω
20
Ω
5
Ω
5.6
Ω
Validate
Solution:
Voltage drop across diode
(
V
D
)
=
0.5
V
Maximum power rating of diode
(
P
)
=
100
mW
=
100
×
10
−
3
W
and source voltage
(
V
s
)
=
1.5
V
.
The resistance of diode
(
R
D
)
=
V
D
2
P
=
(
0.5
)
2
100
×
10
−
3
=
2.5
Ω
And current in diode
(
I
D
)
=
V
D
R
D
=
0.5
2.5
=
0.2
Ω
Therefore total resistance in circuit
(
R
)
=
V
s
I
D
=
1.5
0.2
=
7.5
Ω
And the value of the series resistor
=
Total resistance of the circuit - Resistance of diode
=
7.5
−
2.5
=
5
Ω
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