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Class 12 NEET Physics Semiconductor Electronics Part 2
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© examsnet.com
Question : 38
Total: 43
For CE transistor amplifier, the audio signal voltage across the collector resistance of
2
k
Ω
is 4V. If the current amplification factor of the transistor is 100 and the base resistance is
1
k
Ω
, then the input signal voltage is :
[NEET 2016 P2]
15
mV
10
mV
20
mV
30
mV
Validate
Solution:
A
v
=
β
R
out
R
in
A
v
=
100
×
2
k
Ω
1
k
Ω
⇒
A
v
=
200
A
v
=
(
V
out
)
AC
(
V
m
)
AC
=
200
⇒
(
V
in
)
AC
=
4
200
=
200
mV
© examsnet.com
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