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Test Index
Class 11 NEET Physics System of Particles and Rotational Motion
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© examsnet.com
Question : 43
Total: 109
A small object of uniform density rolls up a curved surface with an initial velocity V . It reaches upto a maximum height of
3
v
2
4
g
with respect to the initial position.The object is
(2013 NEET)
hollow sphere
disc
ring
solid sphere
Validate
Solution:
The kinetic energy of the rolling object is converted into potential energy at height
h
(
=
3
v
2
4
g
)
So by the law of conservation of mechanical energy, we have
1
2
M
v
2
+
1
2
I
ω
2
=
M
g
h
1
2
M
v
2
+
1
2
I
(
v
R
)
2
=
M
g
(
3
v
2
4
g
)
(
∵
ω
=
v
R
)
1
2
I
v
2
R
2
=
3
4
M
v
2
−
1
2
M
v
2
1
2
I
v
2
R
2
=
1
4
M
v
2
or
I
=
1
2
M
R
2
Hence, the object is disc.
© examsnet.com
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