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Class 11 NEET Physics System of Particles and Rotational Motion
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© examsnet.com
Question : 58
Total: 109
Four identical thin rods each of mass M and length l, form a square frame. Moment of inertia of this frame about an axis through the centre of the square and perpendicular to its plane is
(2009)
2
3
M
l
2
13
3
M
l
2
1
3
M
l
2
/
3
M
l
2
Validate
Solution:
Moment of inertia for the rod AB rotating about an axis through the midpoint of AB perpendicular to the plane of the paper is
M
l
2
12
∴ M.I. about the axis passing through the center of the square and parallel to this axis,
I
=
I
0
+
M
d
2
=
M
(
l
2
12
+
l
2
4
)
=
M
l
2
3
For all the four rods,
I
=
4
3
M
l
2
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