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Class 11 NEET Physics System of Particles and Rotational Motion
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© examsnet.com
Question : 63
Total: 109
A thin circular ring of mass M and radius r is rotating about its axis with constant angular velocity
ω
. Two objects each of mass m are attached gently to the opposite ends of a diameter of the ring. The ring now rotates with angular velocity given by
(2010 Mains)
(
M
+
2
m
)
ω
2
m
2
M
ω
M
+
2
m
(
M
+
2
m
)
ω
M
M
ω
M
+
2
m
Validate
Solution:
As no external torque is acting about the axis, angular momentum of system remains conserved.
I
1
ω
1
=
I
2
ω
2
⇒
ω
2
=
I
1
ω
1
I
2
=
M
r
2
ω
(
M
+
2
m
)
r
3
=
M
ω
(
M
+
2
m
)
© examsnet.com
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