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Class 11 NEET Physics Thermodynamics and Kinetic Theory
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© examsnet.com
Question : 50
Total: 105
Two Carnot engines
A
and
B
are operated in series. The engine
A
receives heat from the source at temperature
T
1
and rejects the heat to the sink at temperature
T
. The second engine
B
receives the heat at temperature
T
and rejects to its sink at temperature
T
2
. For what value of
T
the efficiencies of the two engines are equal
(KN NEET 2013)
T
1
−
T
2
2
T
1
T
2
√
T
1
T
2
T
1
+
T
2
2
Validate
Solution:
Efficiency of a Carnot engine,
η
=
1
−
T
2
T
1
where
T
1
is the temperature of source and
T
2
is the temperature of sink respectively.
For engine
A
,
η
A
=
1
−
T
T
1
For engine
B
,
η
B
=
1
−
T
2
T
As per question,
η
A
=
η
B
∴
1
−
T
T
1
=
1
−
T
2
T
⇒
T
T
1
=
T
2
T
or
T
=
√
T
1
T
2
© examsnet.com
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