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Class 11 NEET Physics Waves Questions Questions
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© examsnet.com
Question : 28
Total: 91
The length of the wire between two ends of a sonometer is
100
c
m
.
What should be the positions of two bridges below the wire so that the three segments of the wire have their fundamental frequencies in the ratio 1: 3: 5
(KN NEET 2013)
1500
23
c
m
,
500
23
c
m
1500
23
c
m
,
300
23
c
m
300
23
c
m
,
1500
23
c
m
1500
23
c
m
,
2000
23
c
m
Validate
Solution:
Let
L
(
=
100
c
m
)
be the length of the wire and
L
1
,
L
2
and
L
3
are the lengths of the segments as shown in the figure.
Fundamental frequency,
v
∝
1
L
As the fundamental frequencies are in the ratio of 1: 3: 5 ,
∴
L
1
:
L
2
:
L
3
=
1
1
:
1
3
:
1
5
=
15
:
5
:
3
Let
x
be the common factor. Then
15
x
+
5
x
+
3
x
=
L
=
100
23
x
=
100
or
x
=
100
23
∴
L
1
=
15
×
100
23
=
1500
23
c
m
L
2
=
5
×
100
23
=
500
23
c
m
;
L
3
=
3
×
100
23
=
300
23
c
m
∴
The bridges should be placed from
A
at
1500
23
c
m
and
2000
23
c
m
respectively.
© examsnet.com
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