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Class 11 NEET Physics Waves Questions Questions
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© examsnet.com
Question : 41
Total: 91
A wave in a string has an amplitude of 2 cm. The wave travels in the +ve direction of x axis with a speed of 128 m/sec and it is noted that 5 complete waves fit in 4 m length of the string. The equation describing the wave is
(2009)
y = (0.02) m sin (15.7x - 2010t)
y = (0.02) m sin (15.7x +2010t)
y = (0.02) m sin (7.85x - 1005t)
y = (0.02) m sin (7.85x + 1005t)
Validate
Solution:
Amplitude = 2 cm = 0.02 m, v = 128 m/s
λ
=
4
5
=
0.8
m
;
υ
=
128
0.8
=
160
Hz
ω
=
2
π
υ
=
2
π
×
160
=
1005
;
k
=
2
π
λ
=
2
π
0.8
=
7.85
∴
y
=
0.02
s
i
n
(
7.85
x
−
1005
t
)
© examsnet.com
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