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Class 11 NEET Physics Work, Energy and Power Questions
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© examsnet.com
Question : 69
Total: 89
A particle is projected making an angle of
45
°
with horizontal having kinetic energyK. The kinetic energy at highest point will be
(2001,1997)
K
√
2
K
2
2
K
K
Validate
Solution:
Kinetic energy of the ball
=
K
and angle of projection
(
θ
)
=
45
°
.
Velocity of the ball at the highest point
=
v
cos
θ
=
v
cos
45
°
=
v
√
2
Therefore kinetic energy of the ball
1
2
m
×
(
v
√
2
)
2
=
1
4
m
v
2
=
K
2
.
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