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NIMCET 2011 Question Paper with solutions
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© examsnet.com
Question : 3
Total: 120
If
tan
θ
=
b
a
, then the value of
a
cos
2
θ
+
b
sin
2
θ
is
b
a
a
b
a
a
+
b
Validate
Solution:
Given,
tan
θ
=
b
a
∴
a
cos
2
θ
+
b
sin
2
θ
=
a
(
1
−
tan
2
θ
1
+
tan
2
θ
)
+
b
(
2
tan
θ
1
+
tan
2
θ
)
=
a
(
1
−
b
2
/
a
2
1
+
b
2
/
a
2
)
+
b
(
2
b
/
a
1
+
b
2
/
a
2
)
=
a
(
a
2
−
b
2
a
2
+
b
2
)
+
b
(
2
a
b
a
2
+
b
2
)
=
a
(
a
2
+
b
2
)
a
2
+
b
2
=
a
© examsnet.com
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