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NIMCET 2012 Question Paper with solutions
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© examsnet.com
Question : 2
Total: 120
The number of values of k for which the system of equations (k + 1) x + 8y = 4k and kx + (k + 3) y = 3k - 1 has infinitely many solutions
0
1
2
infinite
Validate
Solution:
Since, the given system has infinitely many solutions
∴
k
+
1
k
=
8
k
+
3
=
4
k
3
k
−
1
Taking 1st and IIIrd part,
(k + 1) (3k - 1) =
4
k
2
⇒
3
k
2
+ 2k - 1 =
4
k
2
⇒
k
2
- 2k + 1 = 0
⇒
(
k
−
1
)
2
= 0
∴ k = 1
© examsnet.com
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