NIMCET 2017 Question Paper with solutions

Let number of breads available be V. According to question, Number of breads robbed by lot thief, = $\frac{x}{2}+\frac{1}{2}$ = $\frac{x+1}{2}$ Now, number of breads left after 1st robbery, = x - $\frac{x+1}{2}$ = $\frac{x-1}{2}$ Again, number of breads robbed by 2nd thief, = $\frac{1}{2}\frac{x-1}{2}+\frac{1}{2}$ = $\frac{x-1}{4}+\frac{1}{2}$ = $\frac{x+1}{2}$ So, number of bread left after 2nd robbery, = $\left(\frac{x-1}{2}\right)-\left(\frac{x+1}{4}\right)$ = $\frac{2x-2-x-1}{4}$ = $\frac{x-3}{4}$ Now, number of breads robbed by 3rd thief, = $\frac{1}{2}\frac{x-3}{4}+\frac{1}{2}$ = $\frac{x-8}{8}+\frac{1}{2}$ = $\frac{x+1}{8}$ Hence, number of breads left after 3rd robbery = $\left(\frac{x-3}{4}\right)-\left(\frac{x-1}{8}\right)$ = $\frac{x-7}{8}$ Now , $\frac{x-7}{8}$ = 3 ⇒ x = 31 Therefore, total number of breads present initially is 31.