NIMCET 2017 Question Paper with solutions

Let number of breads available be V.
According to question,
Number of breads robbed by lot thief,
=

x

2

+

1

2

=

x+1

2

Now, number of breads left after 1st robbery, = x -

x+1

2

=

x−1

2

Again, number of breads robbed by 2nd thief,
=

1

2

(

x−1

2

)+

1

2

=

x−1

4

+

1

2

=

x+1

2

So, number of bread left after 2nd robbery,
= (

x−1

2

)−(

x+1

4

)
=

2x−2−x−1

4

=

x−3

4

Now, number of breads robbed by 3rd thief,
=

1

2

(

x−3

4

)+

1

2

=

x−8

8

+

1

2

=

x+1

8

Hence, number of breads left after 3rd robbery = (

x−3

4

)−(

x−1

8

) =

x−7

8

Now ,

x−7

8

= 3
⇒ x = 31
Therefore, total number of breads present initially is 31.