If A=1 then 1B1 ×11 –––––––––––––– 1B1 1B1× –––––––––––––– 1(B+1)(B+1)1 ––––––––––––––– ∴B+1=C So, different combinations of values of A. B and C = (1.2, 3), (1, 3. 4), (1. 4. 5). (1, 5, 6). (1. 6, 7), (1, 7, 8). (1, 8. 9) Hence. 7 d iffe re n t values of the sum of A. B and C arepossible.