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NIMCET 2020 Question Paper with solutions
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© examsnet.com
Question : 33
Total: 120
Forces of magnitude 5, 3, 1 units acts in the directions
6
i
+
2
j
+
3
k
,
3
i
−
2
j
+
6
k
,
2
i
−
3
j
−
6
k
respectively on a particle which is displaced the point (2, -1, -3) to (5, -1,1). The total work done by the force is
21 units
5 units
33 units
105 units
Validate
Solution:
Given,
→
A
=
2
⋀
i
−
⋀
j
−
3
⋀
k
→
B
=
5
⋀
i
−
⋀
j
+
⋀
k
→
A
B
=
3
⋀
i
+
4
⋀
k
→
F
1
=
5
7
(
6
⋀
i
+
2
⋀
j
+
3
⋀
k
)
→
F
2
=
3
7
(
3
⋀
i
−
2
⋀
j
+
6
⋀
k
)
→
F
3
=
1
7
(
2
⋀
i
−
3
⋀
j
−
6
⋀
k
)
→
F
=
→
F
1
+
→
F
2
+
→
F
3
41
⋀
i
+
⋀
j
+
27
⋀
k
7
→
F
.
→
A
B
=
41
⋀
i
+
⋀
j
+
27
⋀
k
7
(
3
⋀
i
+
4
⋀
k
)
123
+
108
7
=
231
7
=
33
u
n
i
t
s
© examsnet.com
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