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NIMCET 2021 Question Paper with solutions
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© examsnet.com
Question : 54
Total: 120
Study the Following Table, Carefully and answer the following questions
Subject(Full Marks 50)
40
&
above
30
&
above
20
&
above
10
&
above
0
and above
Physics
9
32
80
92
100
Chemistry
4
21
66
81
100
Aggregate
7
27
73
87
100
The number of student scoring less than
40
%
marks in aggregate is ?
13
19
20
27
Validate
Solution:
We have
40
%
of
50
=
(
40
100
×
50
)
=
20
∴ Required number
=
Number of students scoring less than 20 marks in aggregate
=
100
−
Number of students scoring 20 and above marks in aggregate
=
100
−
73
=
27
Less than
40
%
means, less than
20
=
100
−
73
=
27
© examsnet.com
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