Let the sides of the triangle are a,b,c It is given that the perimeter of a triangle ABC is 6 times the Arithmetic Mean of the sines of its angles. ∴a+b+c‌=6(‌
sin‌A+sin‌B+sin‌C
3
) a+b+c‌=2(sin‌A+sin‌B+sin‌C)....(i) From the law of sin, ‌‌