The divergence of the vector A is given bu ÷(A)=∂x∂Ax+∂y∂Ay+∂z∂AzHere Ax=2x+1,Ay=x2−6y,Az=xy2+3zHence ÷(A)=2−6+3=−1If ÷(A)>0, the field is a source field.If ÷(A)<0, the field is a sink field.If ÷(A)=0, the field is a solenoidal field.Since ÷(A)=−1, the vector field is a sink field.