Probability

Concept:Assess whether the events have equal probability.Explanation:When a coin is tossed twice, the sample space is {HH, HT, TH, TT}. Let A = occurrence of one head = {HT, TH}, so $P(A) = \frac{2}{4} = \frac{1}{2}$. Let B = occurrence of two heads = {HH}, so $P(B) = \frac{1}{4}$. Let C = occurrence of no head = {TT}, so $P(C) = \frac{1}{4}$. Since $\frac{1}{2} \neq \frac{1}{4}$, the probabilities are not equal. The events are mutually exclusive and exhaustive, but not equally likely.Answer:The events are not equally likely.